The number of ways to give 16 different things to three pers... | MATH - DEFINITON OF COMBINATIONS, CONDITION COMBINATIONS, DIVISION INTO GROUPS, DERANGEMENTS | SolveeIt | Solveeit

Today, August 24

Question

The number of ways to give 16 different things to three persons A, B, C so that B gets 1 more than A and C gets 2 more than B, is –

A

$\frac{16!}{4!5!7!}$

B

4! 5! 7!

C

$\frac{16!}{3!5!8!}$

D

3! 5! 8!

Answer

$\frac{16!}{4!5!7!}$

Explanation

Solution

No. of things given to A is 4

No. of things given to B is 5

No. of things given to C is 7

\ No. of ways = $\frac{16!}{4!5!7!}$