Question

The number of ways in which 5 girls and 3 boys can be seated in a row so the no two boys are together is

• A. 14040
• B. 14440
• C. 14000
• D. 14400

Answer 1

Answer: (D)

14400

Answer 2

5 girls can be arranged in $5 !=120$ ways
3 boys between 5 girls with positions can be arranged in ${ }^{6} P _{3}=6 \cdot 5 \cdot 4=120$ ways
$\therefore$ Total number of arrangements $=120 \times 120=14400$