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Question: The number of ways in which 5 boys and 3 girls be seated in a row so that each girl is between two b...

The number of ways in which 5 boys and 3 girls be seated in a row so that each girl is between two boys, is

A

2880

B

1880

C

3800

D

2800

Answer

2880

Explanation

Solution

Boys can be seated by

= 5\begin{matrix} 5 \end{matrix} ways. B1 × B2 × B3 × B4 × B5

arrangement of girls in gap between boys = 4P3

so total ways = 5\begin{matrix} 5 \end{matrix} × 4P3 = 2880