Question

The number of ways dividing 52 cards amongst four players equally, are

• A. $\frac{52!}{(13!)^{4}}$
• B. $\frac{52!}{(13!)^{2}4!}$
• C. $\frac{52!}{(12!)^{4}4!}$
• D. None of these

Answer 1

Answer: (A)

$\frac{52!}{(13!)^{4}}$

Answer 2

Required number of ways =$52C_{13} \times^{39}C_{13} \times^{26}C_{13} \times^{13}C_{13}$

= $\frac{52!}{39!13!} \times \frac{39!}{26!13!} \times \frac{26!}{13!13!} \times \frac{13!}{13!}$= $\frac{52!}{(13!)^{4}}$.