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Chemistry Question on Mole concept and Molar Masses

The number of water molecules present in a drop of water (volume 0.0018 mL) density = 18 mL−1mL^{-1} at room temperature is

A

1.084×10181.084 \times 10^{18}

B

6.023×10196.023 \times 10^{19}

C

4.84×10174.84 \times 10^{17}

D

6.023×10236.023 \times 10^{23}

Answer

6.023×10196.023 \times 10^{19}

Explanation

Solution

0.0018 mL=0.0018 g=0.00010.0018 \,mL = 0.0018\, g = 0.0001 mole of water =1×10−4mole= 1 \times 10^{-4} mole. ∴\therefore number of water molecules =6.023×1023×10−4= 6.023 \times 10^{23} \times 10^{-4} =6.023×1019= 6.023 \times 10^{19}