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Question: The number of water molecules present in a drop of water (volume 0.0018 ml) at room temperature is....

The number of water molecules present in a drop of water (volume 0.0018 ml) at room temperature is.

A

6.023×10196.023 \times 10^{19}

B

1.084×10181.084 \times 10^{18}

C

4.84×10174.84 \times 10^{17}

D

6.023×10236.023 \times 10^{23}

Answer

6.023×10196.023 \times 10^{19}

Explanation

Solution

Density=MassVolume= \frac{\text{Mass}}{\text{Volume}}; 1=gml1 = \frac{g}{ml} or g=mlg = ml

0.0018ml = 0.0018gm

No. of moles=weightMolecular weight =0.001818=1×10−4= \frac{\text{weight}}{\text{Molecular weight }} = \frac{0.0018}{18} = 1 \times 10^{- 4}

∴\therefore No. of water molecules 6.023×1023×1×10−46.023 \times 10^{23} \times 1 \times 10^{- 4}

=6.023×1019= 6.023 \times 10^{19}.