Question
Question: The number of values of \(\theta \in \left( {0,2\pi } \right)\) for which the system of linear equat...
The number of values of θ∈(0,2π) for which the system of linear equations
x+3y+7z=0 x+4y+7z=0 (sin3θ)x+(cos2θ)y+2z=0
has a non-trivial solution is:
A. One
B. Three
C. Four
D. Two
Solution
Hint: In the system of linear equations, write the system in the form of
Ax=b and then use the method of determinants to see for which values of the variable the system has a non-trivial solution. Put the determinant of A to be equal to 0 and find the value of the required variable.
Complete step-by-step solution
Let us consider the given system first,
x+3y+7z=0 x+4y+7z=0 (sin3θ)x+(cos2θ)y+2z=0
Write it in the form of Ax=b, where the matrix A contains the coefficients of x, y and z. The matrix x is a column matrix of entries x, y and z and the matrix b is a column matrix containing the entries from the right side of the equation.
\Delta = \left| {\begin{array}{*{20}{c}}
1&3&7 \\
1&4&7 \\
{\sin 3\theta }&{\cos 2\theta }&2
\end{array}} \right| \\
= \left( {8 - 7\cos 2\theta } \right) - 3\left( {2 - 7\sin 3\theta } \right) + 7\left( {\cos 2\theta - 4\sin 3\theta } \right) \\
= 8 - 6 - 7\cos 2\theta + 21\sin 3\theta + 7\cos 2\theta - 28\sin 3\theta \\
= 2 + - 7\sin 3\theta \\