Question

The number of values of ‘k’, for which the system

x = 2y + kz = 1

2x = ky + 8z = 3

does not have a solution, is –

• A. 0
• B. 1
• C. 2
• D. Infinite

Answer 1

Answer: (B)

1

Answer 2

x + 2y + kz = 1

2x + ky + 8z = 3

$\frac{1}{2}$= $\frac{2}{k}$= $\frac{k}{8}$ Ž k = 4

\one value of k for which there is no solution