Question
Mathematics Question on Determinants
The number of values of k for which the linear equations 4x+ky+2z=0 , kx+4y+z=0 and 2x+2y+z=0 possess a non-zero solution is
A
2
B
1
C
5
D
3
Answer
2
Explanation
Solution
Δ=0 ⇒4 k 2k42211=0 ⇒ 4(4−2)−k(k−2)+2(2k−8)=0 ⇒ 8−k2+2k+4k−16=0 k2−6k+8=0 ⇒ (k−4)(k−2)=0 ⇒ k=4,2