Question

The number of turns and radius of cross-section of the coil of a tangent galvanometer are doubled. The reduction factor K will be

• A. K
• B. 2K
• C. 4K
• D. K/4

Answer 1

Answer: (A)

K

Answer 2

$K = \frac { 2 R B _ { H } } { \mu _ { 0 } N }$ (R = radius, N= number of turns)