Question

The number of triangles ABC that can be formed with

$a = 3 , b = 8$ and $\sin A = \frac { 5 } { 3 }$ is

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

Answer: (A)

0

Answer 2

Given, $a = 3 , b = 8$ and $\sin A = \frac { 5 } { 13 }$ .

$\therefore b \sin A = 8 \times \left( \frac { 5 } { 13 } \right) = \frac { 40 } { 13 } > a ( = 3 )$

Thus in this case no triangle is possible.