Chemistry Question on Organic Chemistry- Some Basic Principles and Techniques

Question

The number of sp 3 hybridised carbons in an acyclic neutral compound with molecular formula C4H5N is ________.

Accepted Answer

C4H5N
DBE=(C+1)-( $\frac{H+X-N}{2}$ )
=(4+1)-( $\frac{5-1}{2}$ )=5-2=3
Three double-bond equivalents are present in the compound

Only 1 sp 3 hybridised carbon is there
(Keeping compound as acyclic)