Question
Question: The number of solutions of \(x^{2} + px + q = 0\) is....
The number of solutions of x2+px+q=0 is.
A
2
B
3
C
1
D
None of these
Answer
None of these
Explanation
Solution
We have 5
⇒ ∣x∣2
⇒ esinx−e−sinx−4
But for =0 is not meaningful.
Hence it has no root.