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Question

Mathematics Question on Trigonometry

The number of solutions of the pair of equations 2sin2θcos2θ=02 \sin^2 \theta - \cos 2\theta = 0 and 2cos2θ3sinθ=02 \cos^2 \theta - 3 \sin \theta = 0 in the interval [0,2π][0, 2\pi] is:

A

zero

B

two

C

one

D

four

Answer

two

Explanation

Solution

The correct option is (B):two