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Question

Mathematics Question on Trigonometric Functions

The number of solutions of the equation 2θcos2(θ)+2=02\theta - \cos^2(\theta) + \sqrt{2} = 0 in R is equal to ___________.

Answer

The correct answer is: 1

cos2(θ)=2θ+2\cos^2(\theta) = 2\theta + \sqrt{2}

The number of solutions of the equation 2θ−cos2⁡θ+√2=0 in R is equal to

1 point of intersection = 1 solution.