Question

The number of solutions of $a \neq 0$.

• A. 3
• B. 1
• C. 2
• D. 0

Answer 1

Answer: (B)

1

Answer 2

$\frac{p + q - x}{r} + \frac{q + r - x}{p}$ $\frac{r + p - x}{q}$

$\frac{4x}{p + q + r} = 0$ $x = p + q + r$

$x = p - q + r$2 but $x = \frac{p + q}{q + r}$ when $x = \frac{p}{q} + r$

$x^{2} - 5|x| + 6 = 0$only solution is $(m^{2} + 1)x^{2} + 2amx + a^{2} - b^{2} = 0$

$a^{2} + b^{2}(m^{2} + 1) = 0$Hence number of solution is one.