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Question: The number of solutions for the equation \({{\text{z}}^2} + |{\text{z| = 0}}\) is \( {\text{A}...

The number of solutions for the equation z2+z| = 0{{\text{z}}^2} + |{\text{z| = 0}} is
A. 1 B. 2 C. 3 D. 4  {\text{A}}{\text{. 1}} \\\ {\text{B}}{\text{. 2}} \\\ {\text{C}}{\text{. 3}} \\\ {\text{D}}{\text{. 4}} \\\

Explanation

Solution

Hint: We write the given complex number in terms of x and y and substitute in the equation. Comparing the real and imaginary components, we determine x and y. That gives us the values of z.

Step-by-step answer:
Here z is a complex number and it is of the form
z = x + iy --- (i = imaginary number, i = (1)\sqrt {\left( { - 1} \right)} )

Now, z2=(x + iy)2{{\text{z}}^2} = {\left( {{\text{x + iy}}} \right)^2}
= x2+(iy)2+2xiy{{\text{x}}^2} + {\left( {{\text{iy}}} \right)^2} + {\text{2xiy}} -- (i2=1{{\text{i}}^2} = - 1)
= x2y2+2xiy{{\text{x}}^2} - {{\text{y}}^2} + {\text{2xiy}}

|z| = x2+y2\sqrt {{{\text{x}}^2} + {{\text{y}}^2}}
Mod z, denoted by |z| is the absolute/scalar value of z and is given by the above.

Therefore, z2+z| = 0{{\text{z}}^2} + |{\text{z| = 0}}
x2y2+2xiy + x2+y2=0\Rightarrow {{\text{x}}^2} - {{\text{y}}^2} + {\text{2xiy + }}\sqrt {{{\text{x}}^2} + {{\text{y}}^2}} = 0
(0 can be written as 0 + i0)
x2y2+2xiy + x2+y2=0+i0\Rightarrow {{\text{x}}^2} - {{\text{y}}^2} + {\text{2xiy + }}\sqrt {{{\text{x}}^2} + {{\text{y}}^2}} = 0 + {\text{i0}}

Comparing real components and imaginary components on both sides, we get

Real components: Imaginary components:

x2y2 + x2+y2=0{{\text{x}}^2} - {{\text{y}}^2}{\text{ + }}\sqrt {{{\text{x}}^2} + {{\text{y}}^2}} = 0 2ixy = i0
⟹xy = 0
⟹x = 0 or y = 0

Case I:

When y = 0

Real part,
x2 + x2=0{{\text{x}}^2}{\text{ + }}\sqrt {{{\text{x}}^2}} = 0
x2 + |x|=0{{\text{x}}^2}{\text{ + |x|}} = 0
⟹x = 0
If x = 0 and y = 0 ⟹ z = x + iy = 0

Case 2:

When x = 0

Real part,
 - y2+y2=0{\text{ - }}{{\text{y}}^2} + \sqrt {{{\text{y}}^2}} = 0
 - y2+y|=0{\text{ - }}{{\text{y}}^2} + |{\text{y|}} = 0
⟹|y| (|y| - 1) = 0
⟹y = 0, +1, -1

Here y cannot be 0 since that case already exists.
Hence, y = +1,-1

Thus we have, x = 0, y = +1 and x = 0, y = -1, therefore z = 0 + 1(i) = +i and z = 0 -1(i) = -i

The solutions of the equation z2+z| = 0{{\text{z}}^2} + |{\text{z| = 0}} are 0, +i, -i.

Hence there are 3 solutions. Option C is the correct answer.

Note: The key in solving such types of problems is to write the complex number in terms of real number x terms and imaginary number y terms. Correctly comparing the real and imaginary components in the equation is a crucial step. We ignore the case y = 0 in step 2 as it is already covered in step 1.
And i =(1)\sqrt {\left( { - 1} \right)} .