Question
Question: The number of solutions for the equation \({{\text{z}}^2} + |{\text{z| = 0}}\) is \( {\text{A}...
The number of solutions for the equation z2+∣z| = 0 is
A. 1 B. 2 C. 3 D. 4
Solution
Hint: We write the given complex number in terms of x and y and substitute in the equation. Comparing the real and imaginary components, we determine x and y. That gives us the values of z.
Step-by-step answer:
Here z is a complex number and it is of the form
z = x + iy --- (i = imaginary number, i = (−1))
Now, z2=(x + iy)2
= x2+(iy)2+2xiy -- (i2=−1)
= x2−y2+2xiy
|z| = x2+y2
Mod z, denoted by |z| is the absolute/scalar value of z and is given by the above.
Therefore, z2+∣z| = 0
⇒x2−y2+2xiy + x2+y2=0
(0 can be written as 0 + i0)
⇒x2−y2+2xiy + x2+y2=0+i0
Comparing real components and imaginary components on both sides, we get
Real components: Imaginary components:
x2−y2 + x2+y2=0 2ixy = i0
⟹xy = 0
⟹x = 0 or y = 0
Case I:
When y = 0
Real part,
⟹x2 + x2=0
⟹x2 + |x|=0
⟹x = 0
If x = 0 and y = 0 ⟹ z = x + iy = 0
Case 2:
When x = 0
Real part,
⟹ - y2+y2=0
⟹ - y2+∣y|=0
⟹|y| (|y| - 1) = 0
⟹y = 0, +1, -1
Here y cannot be 0 since that case already exists.
Hence, y = +1,-1
Thus we have, x = 0, y = +1 and x = 0, y = -1, therefore z = 0 + 1(i) = +i and z = 0 -1(i) = -i
The solutions of the equation z2+∣z| = 0 are 0, +i, -i.
Hence there are 3 solutions. Option C is the correct answer.
Note: The key in solving such types of problems is to write the complex number in terms of real number x terms and imaginary number y terms. Correctly comparing the real and imaginary components in the equation is a crucial step. We ignore the case y = 0 in step 2 as it is already covered in step 1.
And i =(−1).