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Question

Mathematics Question on General and Particular Solutions of a Differential Equation

The number of solutions for the equation Sin2x+Cos  4x=2Sin\, 2x + Cos \; 4x = 2 is

A

00

B

11

C

22

D

\infty

Answer

00

Explanation

Solution

Given, sin2x+cos4x=2\sin 2 x+\cos 4 x=2
sin2x+12sin22x=2\Rightarrow \,\,\,\,\sin 2 x+1-2 \sin ^{2} 2 x=2
2sin22xsin2x+1=0\Rightarrow \,\,\,\,\,2 \sin ^{2} 2 x-\sin 2 x+1=0
Now, Discriminant, D=(1)24×2×1=7<0D=(-1)^{2}-4 \times 2 \times 1=-7 < 0
Hence, it is an imaginary equation, so the real roots does not exist.