Question
Mathematics Question on General and Particular Solutions of a Differential Equation
The number of solutions for the equation Sin2x+Cos4x=2 is
A
0
B
1
C
2
D
∞
Answer
0
Explanation
Solution
Given, sin2x+cos4x=2
⇒sin2x+1−2sin22x=2
⇒2sin22x−sin2x+1=0
Now, Discriminant, D=(−1)2−4×2×1=−7<0
Hence, it is an imaginary equation, so the real roots does not exist.