Question

The number of solution of log_sinx2^tanx> 0 in the interval

$\left( 0,\frac{\pi}{2} \right)$ is

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

Answer: (A)

0

Answer 2

log_sinx 2^tanx > 0 sinx > 0 sinx ¹ 1

0 < sin x < 1 in $\left( 0,\frac{\pi}{2} \right)$

2^tanx < 1 (not possible)

\ No solution