Question
Question: The number of sodium atoms in \[2{\text{ }}moles\] of sodium ferrocyanide is: \[ A.\;12{\text{...
The number of sodium atoms in 2 moles of sodium ferrocyanide is:
A.12 X 1023 B.26 X 1023 C.34 X 1023 D.48 X 1023Solution
We must remember the molecular formula for Sodium ferrocyanide is Na4[Fe(CN)6]. 1 mole of the compound is having 4 molesofNa. Generally one mole of a substance is equal to 6.022×1023. The number 6.022×1023 is known as Avogadro number.
Complete step by step answer:
Let’s start with writing the molecular formula for sodium ferrocyanide. As the name suggests it is a complex compound having 2 components which are metal and a complex. The complex consists of iron (Fe) and cyanide (CN). As we can see the iron is in a ferrous state means having 2+ oxidation states. Also 6 CN are connected with iron so the overall oxidation state of the complex is -4. Hence, 4 Na+ will be attached with the complex and the compounds molecular formula will be Na4[Fe(CN)6].
1 mole of Na4[Fe(CN)6] is having 4 moles of sodium, and one mole of compound is having 6.022 × 1023 times the atom. So, 4 moles of sodium will be having 4 × 6.022 × 1023 atoms.
Similarly, in case of 2 moles, 2 times the atom in 1 mole will be present so, 8 moles of sodium will be there and hence 8 × 6.022 × 1023 atoms which will be equal to 48 × 1023 atoms.
So, the answer to this question is D. 48 × 1023 atoms.
Note: We must know that the Avogadro’s number is being a boon for scientists as it helps in calculating, discussing and comparing very high numbers of atomic and subatomic particles. Avogadro’s number is 6.022 × 1023. Avogadro’s number becomes very useful because in everyday life the substances contain a large number of atoms and molecules.