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Question: The number of sodium atoms in \[2{\text{ }}moles\] of sodium ferrocyanide is: \[ A.\;12{\text{...

The number of sodium atoms in 2 moles2{\text{ }}moles of sodium ferrocyanide is:

A.  12 X 1023 B.  26 X 1023 C.  34 X 1023 D.  48 X 1023  A.\;12{\text{ }}X{\text{ }}{10^{23}} \\\ B.\;26{\text{ }}X{\text{ }}{10^{23}} \\\ C.\;34{\text{ }}X{\text{ }}{10^{23}} \\\ D.\;48{\text{ }}X{\text{ }}{10^{23}} \\\
Explanation

Solution

We must remember the molecular formula for Sodium ferrocyanide is Na4[Fe(CN)6]N{a_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right]. 1 mole1{\text{ }}mole of the compound is having 4 moles4{\text{ }}molesofNaNa. Generally one mole of a substance is equal to 6.022×10236.022 \times {10^{23}}. The number 6.022×10236.022 \times {10^{23}} is known as Avogadro number.

Complete step by step answer:
Let’s start with writing the molecular formula for sodium ferrocyanide. As the name suggests it is a complex compound having 2 components which are metal and a complex. The complex consists of iron (Fe)\left( {Fe} \right) and cyanide (CN)\left( {CN} \right). As we can see the iron is in a ferrous state means having 2+ oxidation states. Also 6 CNCN are connected with iron so the overall oxidation state of the complex is -4. Hence, 4 Na+N{a^ + } will be attached with the complex and the compounds molecular formula will be Na4[Fe(CN)6]N{a_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right].
1 mole1{\text{ }}mole of Na4[Fe(CN)6]N{a_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right] is having 4 moles4{\text{ }}moles of sodium, and one mole of compound is having 6.022 × 10236.022{\text{ }} \times {\text{ }}{10^{23}} times the atom. So, 4 moles4{\text{ }}moles of sodium will be having 4 × 6.022 × 10234{\text{ }} \times {\text{ }}6.022{\text{ }} \times {\text{ }}{10^{23}} atoms.
Similarly, in case of 2 moles2{\text{ }}moles, 2 times the atom in 1 mole1{\text{ }}mole will be present so, 8 moles8{\text{ }}moles of sodium will be there and hence 8 × 6.022 × 10238{\text{ }} \times {\text{ }}6.022{\text{ }} \times {\text{ }}{10^{23}} atoms which will be equal to 48 × 102348{\text{ }} \times {\text{ }}{10^{23}} atoms.

So, the answer to this question is D. 48 × 102348{\text{ }} \times {\text{ }}{10^{23}} atoms.

Note: We must know that the Avogadro’s number is being a boon for scientists as it helps in calculating, discussing and comparing very high numbers of atomic and subatomic particles. Avogadro’s number is 6.022 × 10236.022{\text{ }} \times {\text{ }}{10^{23}}. Avogadro’s number becomes very useful because in everyday life the substances contain a large number of atoms and molecules.