Question

The number of sodium atoms in $2$ moles of sodium ferrocyanide is:

• A. $12\times {{10}^{23}}$
• B. $26\times {{10}^{23}}$
• C. $34\times {{10}^{23}}$
• D. $48\times {{10}^{23}}$

Answer 1

Answer: (D)

$48\times {{10}^{23}}$

Answer 2

Formula $Na _{4}\left[ Fe ( CN )_{6}\right]$ sodium ferrocyanide suggests that it has four sodium atoms.
Number of $Na$ atoms $=$ no. of moles $\times$ no. of atoms per molecule $\times$ Avogadro number
$=2 \times 4 \times 6: 023 \times 10^{23}$
$=48 \times 10^{23}$