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Question

Mathematics Question on Permutations

The number of six digit numbers, whose all digits are odd (i.e., 1,3,5,7,9)1 , 3 , 5 , 7 , 9 ), is

A

656^{5}

B

565^{6}

C

6!2!\frac{6!}{2!}

D

None of these

Answer

565^{6}

Explanation

Solution

Since six digit numbers whose all digits are odd out of only five available digits 1,3,5,7,91, 3, 5, 7, 9 are to be formed suggests that repetition of digits is must. Hence required numbers is 565^6.