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Question: The number of silver atoms present in a \[90\% \] pure silver wire weighing \[10{\text{g}}\] is: A...

The number of silver atoms present in a 90%90\% pure silver wire weighing 10g10{\text{g}} is:
A.5.57×10225.57 \times {10^{22}}
B.0.62×10230.62 \times {10^{23}}
C.5.0×10225.0 \times {10^{22}}
D.6.2×10296.2 \times {10^{29}}

Explanation

Solution

:Hint: Try to find the number of moles of silver in the given mass of substance. Use the number of moles of silver to find the number of atoms present in that amount of silver using the Avogadro’s number 6.022×10236.022 \times {10^{23}} .

Complete step by step answer:
First we will calculate the number of moles of silver present in the given amount of substance. As it is given in the question that the silver wire is 90%90\% pure which means 100g100{\text{g}} of pure wire contains only 90g90{\text{g}} of silver by mass in it. Since, the mass of given wire is 10g10{\text{g}} , thereby it contains 9g9{\text{g}} pure silver and 1g1{\text{g}} other substance in it. Now, to calculate number of moles of silver in 9g9{\text{g}} of pure silver, we can use the formula:
number of moles=given mass(in gram)molar mass(gmol1){\text{number of moles}} = \dfrac{{{\text{given mass}}\left( {{\text{in gram}}} \right)}}{{{\text{molar mass}}\left( {{\text{gmo}}{{\text{l}}^{ - 1}}} \right)}} , putting the given mass of silver which is 9g9{\text{g}} and as we know molar mass or mass of 1 mole of silver equals to 108gmol1108{\text{gmo}}{{\text{l}}^{ - 1}} , we get: number of moles=9108=0.083{\text{number of moles}} = \dfrac{9}{{108}} = 0.083 .
Now 1 mole of substance contains NA{{\text{N}}_{\text{A}}} entities or 6.022×10236.022 \times {10^{23}} entities, as we have 0.083mol0.083{\text{mol}} of silver, the number of atoms of silver in 0.083mol0.083{\text{mol}} can be given as:
number of atom=number of moles×6.022×1023{\text{number of atom}} = {\text{number of moles}} \times 6.022 \times {10^{23}} , number of atom=0.083×6.022×1023{\text{number of atom}} = 0.083 \times 6.022 \times {10^{23}} .
On solving, we get number of atoms in 0.083mol0.083{\text{mol}} of silver or we can say in 90%90\% pure silver wire weighing 10g10{\text{g}} equals to 0.5×10230.5 \times {10^{23}} atoms.

Thus, the correct option is C. As 0.5×10230.5 \times {10^{23}} equals to 5.0×10225.0 \times {10^{22}} .
Note:
Mole is the SI unit of amount of substance. It is defined as the amount of a substance that contains as many entities as there are atoms present in exactly 12g12{\text{g}} of carbon (C12)\left( {{{\text{C}}^{12}}} \right). Mole is a concept of quantity in terms of number, mass and volume. For a given balanced equation, information of reactant or product can be determined if information of one of the species is given either in terms of moles, molecules or weight. 1 mole is equivalent to NA{{\text{N}}_{\text{A}}} atoms, molecules, ion, or electrons. 1 mole is equivalent to molecular weight or atomic weight of a substance. 1 mole is equivalent to the volume of 22.4L22.4{\text{L}} of any gas occupied at NTP condition.