Question
Mathematics Question on Trigonometric Functions
The number of real solutions of the equation (sinx−x)(cosx−x2)=0 is
A
1
B
2
C
3
D
4
Answer
3
Explanation
Solution
Given, (sinx−x)(cosx−x2)=0
⇒sinx=x or cosx=x2
Now, if sinx=x, then only one solution i.e. x=0 is possible.
Also, if cosx=x2, then two solutions are possible.
Hence, there are total 3 solutions.