Question

The number of real solutions of the equation $3\left(x^2+\frac{1}{x^2}\right)-2\left(x+\frac{1}{x}\right)+5=0$, is

• A. 4
• B. 3
• C. 2
• D. 0

Answer 1

Answer: (D)

0

Answer 2

The correct answer is (D) : 0
3(x2+x21​)−2(x+x1​)+5=0
3[(x+x1​)2−2]−2(x+x1​)+5=0
Let x+x1​=t
3t2−2t−1=0
3t2−3t+t−1=0
3t(t−1)+1(t−1)=0
(t−1)(3t+1)=0
t=1,−31​
x+x1​=1,−31​⇒ No solution.