Question
Chemistry Question on Quantum Mechanical Model of Atom
The number of radial nodes and angular nodes for d-orbital can be represented as
A
(n-2) radial nodes + 1 angular node = (n - 1) total nodes
B
(n-1) radial nodes + 1 angular node = (n - 1) total nodes
C
(n-3) radial nodes + 2 angular nodes = (n - l - 1) total nodes
D
(n-3) radial nodes + 2 angular nodes = (n - l) total nodes
Answer
(n-3) radial nodes + 2 angular nodes = (n - l) total nodes
Explanation
Solution
Total number of nodes = n - 1 For d-orbital, radial nodes = n - 3 and there are 2 angular nodes. The number of angular nodes is given by l. i.e., for p, 1 angular node, for d , 2 angular nodes and so on.