Question
Question: The number of potassium atoms present in 117 g of potassium sample (Molecular Weight = 39 g/mole) ar...
The number of potassium atoms present in 117 g of potassium sample (Molecular Weight = 39 g/mole) are:
A. 39×6.023×1023atoms
B. 117×6.023×1023atoms
C. 4×6.023×1023atoms
D. 3×6.023×1023atoms
Solution
The molecular weight of potassium is 39 g/mole . This means the weight of 1 mole potassium which contains 6.023 × 1023 number of atoms is 39 g. To calculate the number of potassium in 117 grams of potassium, you should know the mole concept.
Formula used: 1 mole = atomic weight = 6.023×1023no.of atoms
Step by step solution:
Now at first, according to the mole concept we know 1 mole of any substance is equal to its molecular weight. And 1 mole is also equal to the Avogadro’s number of atoms i.e.6.023×1023.
Therefore,1 mole = atomic weight = 6.023×1023no.of atoms
According to this it can be said that 39 gm potassium contains 6.023×1023 number of atoms.
39 gm potassium contains 6.023×1023 number of atoms.
Now, 1 gram potassium contains 396.023×1023 number of atoms
So, 117 grams potassium contains 396.023×1023×117 number of atoms.
Therefore, 117 grams potassium contains 3×6.023×1023 number of atoms.
So, the correct option is D.
Note: The formula of equivalent weight is,
Equivalent weight = number of equivalent molesMolecular weight.
For acids the number of equivalents is equal to the number of H+ present in one molecule. And for bases the number of HO- groups present in one molecule. The equivalent weight of any substance cannot be greater than its molecular weight. Either the value of equivalent weight is equal or less than the molecular weight of that substance.