Question

The number of possible alcohol isomers for $C_4H_{10}O$ is

• A. $4$
• B. $3$
• C. $2$
• D. $5$

Answer 1

Answer: (A)

$4$

Answer 2

Possible alcohol isomers of $C_4 H_{10}O$ is $4$.
$(i) CH_3CH_2CH_2OH$
$1$-butanol ($n$-butyl alcohol)
$(ii) \,CH_3CH_2 - \underset{\overset{|}{O}{H}}{C} H - CH_3$
$2$-butanol (sec-butyl alcohol)
$(iii)\, (CH_3)_2 CHCH_2OH$
$2$-methyl-l-propanol (iso-butyl alcohol)

$2$-methyl-$2$-propanol (t-butyl alcohol)