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Question: The number of points on the line 3x + 4y = 5, which are at a distance of sec<sup>2</sup>q + 2 cosec<...

The number of points on the line 3x + 4y = 5, which are at a distance of sec2q + 2 cosec2q, qĪ R, from the point (1, 3), is-

A

1

B

2

C

3

D

Infinite

Answer

2

Explanation

Solution

The perpendicular distance of (1, 3) from the line 3x + 4y =5 is 2 units while,

sec2q + 2 cosec2q ³ 3 {as sec2q, cosec2 q ³ 1}

Evidently, these will be two such points on the line.