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Question: The number of $\pi$ bonds and $\sigma$-bonds in case of lewis structure of $SO_4^{2-}$....

The number of π\pi bonds and σ\sigma-bonds in case of lewis structure of SO42SO_4^{2-}.

A

4σ,2π4\sigma, 2\pi

B

4σ,1π4\sigma, 1\pi

C

4σ4\sigma, zero π\pi

D

4σ,4π4\sigma, 4\pi

Answer

Option (A) — 4σ,2π4\sigma, 2\pi

Explanation

Solution

In the resonance hybrid of the sulfate ion, SO42\text{SO}_4^{2-}, there are four equivalent S–O bonds. Each bond is composed of one sigma (σ\sigma) bond, and the delocalized pi (π\pi) bonding accounts for a total of 2 pi bonds spread over the structure.

Thus, the Lewis structure effectively contains 4 sigma bonds and 2 pi bonds.

Explanation (minimal):

  • 4 S–O bonds → each bond has 1 σ\sigma bond.
  • Delocalized π\pi bonds in the resonance structure contribute a total of 2 π\pi bonds.