Question

The number of permutations of taking all letters and keeping the vowels of the words in the odd places is

• A. $96$
• B. $144$
• C. $512$
• D. $576$

Answer 1

Answer: (D)

$576$

Answer 2

Number of odd places $1, 3, 5, 7$ i.e., $4$ Vowels are $O, I, E$ $\therefore$ reqd. number of ways $=\,^{4}P_{3}\times4!=24\times24$ $=576$