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Question

Mathematics Question on Permutations

The number of permutations of 4 letters that can be made out of the letters of the word EXAMINATION is

A

24542454

B

24522452

C

24502450

D

18061806

Answer

24542454

Explanation

Solution

In a word EXAMINATION has 2A,2I,2N,E,M,O,T,X,2A,\,2I,\,2N,\,E,\,M,\,O,\,T,\,X, therfore 7 letters can be chosen in following ways Case I when 2 alike of one kind and 2 alike of second kind of is
3C2^{3}{{C}_{2}} .
\therefore Number of words =3C2×4!2!2!=18{{=}^{3}}{{C}_{2}}\times \frac{4!}{2!\,\,2!}=18
Case II when 2 alike of one kind and 2 different ie,
3C1×7C2.^{3}{{C}_{1}}{{\times }^{7}}{{C}_{2}}.
\therefore Number of words =3C1×7C2×4!2!{{=}^{3}}{{C}_{1}}{{\times }^{7}}{{C}_{2}}\times \frac{4!}{2!}
=756=756 Case III when all are different. ie, 8C4^{8}{{C}_{4}} .
\therefore Number of words =8C4×4!=1680{{=}^{8}}{{C}_{4}}\times 4!=1680
Hence, total number of words =18+756+1680=18+756+1680
=2454=2454