Question
Mathematics Question on Permutations
The number of permutations of 4 letters that can be made out of the letters of the word EXAMINATION is
A
2454
B
2452
C
2450
D
1806
Answer
2454
Explanation
Solution
In a word EXAMINATION has 2A,2I,2N,E,M,O,T,X, therfore 7 letters can be chosen in following ways Case I when 2 alike of one kind and 2 alike of second kind of is
3C2 .
∴ Number of words =3C2×2!2!4!=18
Case II when 2 alike of one kind and 2 different ie,
3C1×7C2.
∴ Number of words =3C1×7C2×2!4!
=756 Case III when all are different. ie, 8C4 .
∴ Number of words =8C4×4!=1680
Hence, total number of words =18+756+1680
=2454