Question

The number of neutrons released when $92U^{235}$

undergoes fission by absorbing $0n^{1}$ and

$(_{56}Ba^{144} +_{36}Kr^{89})$ are formed, is.

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

Answer: (D)

3

Answer 2

$92U^{235} +_{0}n^{1} \rightarrow_{92}U^{236}$and

$92U^{236} \rightarrow_{56}Ba^{144} +_{36}Kr^{89} + 3_{0}n^{1} + Q$.