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Question

Chemistry Question on Mole concept and Molar Masses

The number of neutrons in 1.8 g of water will approximately be

A

4.216×10234.216 \times 10^{23}

B

8.432×10238.432 \times 10^{23}

C

4.816×10234.816 \times 10^{23}

D

4.216×10244.216 \times 10^{24}

Answer

4.816×10234.816 \times 10^{23}

Explanation

Solution

H2O=211H+816OH_{2}O=2_{1}^{1}H+^{16}_{8}O ∴\therefore neutrons 01n=0+8^{1}_{0}n=0+8 nH2O=1.818=0.1^{n}H_{2}O=\frac{1.8}{18}=0.1 Hence 01n=8×0.1×6.02×1023^{1}_{0}n=8\times0.1\times6.02\times10^{23} =4.816×1023=4.816\times10^{23}