Question: The number of moles of $K_{2}Cr_{2}O_{7}$reduced by one mole of $Sn^{2 +}$ ions is....

Question

The number of moles of $K_{2}Cr_{2}O_{7}$ reduced by one mole of $Sn^{2 +}$ ions is.

Answer 1

$Cr_{2}O_{7}^{2 -} + 3Sn^{2 +} + 14H^{+} \rightarrow 2Cr^{3 +} + 3Sn^{4 +} + 7H_{2}O$

1 mole of $Sn^{2 +}$ will reduce $\frac{1}{3}$ moles of $K_{2}Cr_{2}O_{7}$

Question: The number of moles of \(K_{2}Cr_{2}O_{7}\)reduced by one mole of \(Sn^{2 +}\) ions is....