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Question

Chemistry Question on Classical Idea Of Redox Reactions – Oxidation And Reduction Reactions

The number of moles of electron required to reduce 0.2 mole of Cr2O-27 to Cr+3

A

12

B

0.6

C

1.2

D

6

Answer

1.2

Explanation

Solution

Cr2+6O72−Cr_{2}^{+6}O_{7}^{2-} −>[6e−]{ ->[6e^{-}] } 2Cr+32 Cr^{+3}
1 mol requires 6 mole of electrons
0.2 mol requires 0.2×61=1.2 \frac{0.2\times6}{1}=1.2 \, mol of electrons