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Question: The number of molecules in a gas at pressure 1.64 × 10<sup>–3</sup> atmospheres and temperature 200 ...

The number of molecules in a gas at pressure 1.64 × 10–3 atmospheres and temperature 200 K having the volume 1 cc are-

A

6.02 × 1016

B

2.63 × 1016

C

3.01 × 1019

D

12.04 × 1019

Answer

6.02 × 1016

Explanation

Solution

PV = NKT Ž N = PVKT\frac{PV}{KT}

=(1.64×10−3×1.01×105)×(1×10−6)1.38×10−23×200\frac{(1.64 \times 10^{- 3} \times 1.01 \times 10^{5}) \times (1 \times 10^{- 6})}{1.38 \times 10^{- 23} \times 200}= 6.02 × 1016