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Chemistry Question on Mole concept and Molar Masses

The number of molecules in 4.25 g4.25\, g of ammonia is approximately

A

3.5×10233 . 5 \times 10^{23}

B

0.5×10230 . 5 \times 10^{23}

C

2.5×10232.5 \times 10^{23}

D

1.5×10231.5 \times 10^{23}

Answer

1.5×10231.5 \times 10^{23}

Explanation

Solution

Given: Weight of ammonia =4×25 g.=4 \times 25\, g . We know that 17 g17\, g of ammonia (NH3)\left( NH _{3}\right) contains 6×02×10236 \times 02 \times 10^{23} molecules. Therefore number of molecules in 4×254 \times 25 of NH3=6×02×1023×4×2517NH _{3}= \frac{6 \times 02 \times 10^{23} \times 4 \times 25}{17} =1×50×1023=1 \times 50 \times 10^{23}