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Chemistry Question on Mole concept and Molar Masses

The number of molecules in 100m L of 0.02N H2SO4H_2SO_4 is

A

6.02×10226.02 \times 10^{22}

B

6.02×10216.02 \times 10^{21}

C

6.023×10206.023 \times 10^{20}

D

6.02×10186.02 \times 10^{18}

Answer

6.023×10206.023 \times 10^{20}

Explanation

Solution

For H2SO4H_2SO_4, Normality, N = 2M or M = N2=0.022=0.01\frac{N}{2} = \frac{0.02}{2} = 0.01 Moles of H2SO4=0.01×1001000=1×10−3H_2SO_4 = \frac{0.01 \times 100}{1000} = 1 \times 10^{-3} ∴\therefore Number of molecules in 100 mL of 0.02 N H2SO4=1×10−3×NAH_2SO_4 = 1 \times 10^{-3} \times N_A = 1×10−3×6.023×10231 \times 10^{-3} \times 6.023 \times 10^{23} = 6.023×10206.023 \times 10^{20}