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Question: The number of mole of oxygen in one litre of air containing \(21\% \) oxygen by volume, under standa...

The number of mole of oxygen in one litre of air containing 21%21\% oxygen by volume, under standard condition is :
(A). 0.0093mole0.0093mole
(B). 2.10mole2.10mole
(C). 0.186mole0.186mole
(D). 0.21mole0.21mole

Explanation

Solution

21%21\% of oxygen is present in air by volume means that 21 ml21{\text{ ml}} of oxygen is present in 100 ml100{\text{ ml}} volume of air. At STP conditions, 11 mole contains 22.4 L22.4{\text{ L}}of a substance/air.

Complete step by step answer:
As we know that a mole is defined as the amount of substance which has mass equal to gram atomic or molecular mass or if it contains Avogadro no.(6.022×1023)\left( {6.022 \times {{10}^{23}}} \right) of atoms/molecules.
The atomic mass of an element is the number of times an atom of the element is heavier than an atom of carbon taken as 1212 . The atomic mass of an element expressed in gram is called gram atomic mass and the molecular mass of a substance expressed in gram is called gram molecular mass.
For a gas, a mole is defined as the amount of gas which has a volume of 22.4 L22.4{\text{ L}} or 22400 ml 22400{\text{ ml }} at STP.
Now according to question, an air of volume 1 L1{\text{ L}} contains 21%21\% of oxygen by volume. This means that amount of oxygen present in air is 21%21\% of 1 L of air = 21100×11{\text{ L }}\operatorname{of} {\text{ }}\operatorname{air} {\text{ = }}\dfrac{{21}}{{100}} \times 1
=0.21L= 0.21L
This implies that 0.21L0.21L of oxygen is present in 1 L1{\text{ L}} of air. At STP conditions, 11 mole gas is equal to 22.4 L22.4{\text{ L}} volume.
That is,
22.4 L22.4{\text{ L}} of oxygen contains mole  = 1 mole{\text{ = 1 mole}}
0.21 L\therefore 0.21{\text{ L}} of oxygen mole  = 0.2122.4=0.093 mole {\text{ = }}\dfrac{{0.21}}{{22.4}} = 0.093{\text{ mole}}
Thus the required number of moles of oxygen is 0.093mole0.093mole.
Hence, option (A) is the correct answer.

Note: The STP Condition is known as standard temperature-pressure condition. The value of temperature at STP is 273K273K and pressure at STP is 1atm1\operatorname{atm} . If the pressure is changed to 22.7 L22.7{\text{ L}} that condition is generally known as NTP condition (normal temperature-pressure condition).