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Question: The number of lines that are parallel to \(2 x + 6 y + 7 = 0\) and have an intercept of length 10 be...

The number of lines that are parallel to 2x+6y+7=02 x + 6 y + 7 = 0 and have an intercept of length 10 between the coordinate axes is.

A

1

B

2

C

4

D

Infinitely many

Answer

2

Explanation

Solution

The equation of any line parallel to 2x+6y+7=02 x + 6 y + 7 = 0 is 2x+6y+k=02 x + 6 y + k = 0 .

This meets the axes at A(k2,0)A \left( - \frac { k } { 2 } , 0 \right)and B(0,k6)B \left( 0 , - \frac { k } { 6 } \right) .

By hypothesis, AB=10A B = 10

k24+k236=1010k236=10\Rightarrow \sqrt { \frac { k ^ { 2 } } { 4 } + \frac { k ^ { 2 } } { 36 } } = 10 \Rightarrow \sqrt { \frac { 10 k ^ { 2 } } { 36 } } = 10

10k2=3600k=±61010 k ^ { 2 } = 3600 \Rightarrow k = \pm 6 \sqrt { 10 }.

Hence there are two lines given by 2x+6y±610=02 x + 6 y \pm 6 \sqrt { 10 } = 0.