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Question: The number of ions give by \(\lbrack Pt(NH_{3})_{6}\rbrack Cl_{4}\)in aqueous solutions will be...

The number of ions give by [Pt(NH3)6]Cl4\lbrack Pt(NH_{3})_{6}\rbrack Cl_{4}in aqueous solutions will be

A

Two

B

Three

C

Five

D

Eleven.

Answer

Five

Explanation

Solution

[Pt(NH3)6Cl4]\lbrack Pt(NH_{3})_{6}Cl_{4}\rbrack [Pt(NH3)6]4++4Cl−\lbrack Pt(NH_{3})_{6}\rbrack^{4 +} + 4Cl^{-}

Total number of ions given in aqueous solutions = 5