Question

The number of ions formed when cuprammonium sulphate is dissolved in water is.

• A. 1
• B. 2
• C. 4
• D. Zero

Answer 1

Answer: (B)

2

Answer 2

Cuprammonium salt -$\lbrack Cu(NH_{3})_{4}\rbrack SO_{4}$

$\lbrack Cu(NH_{3})_{4}\rbrack SO_{4}$⇌$\lbrack Cu(NH_{3})_{4}\rbrack^{2 +} + SO_{4}^{2 -}$

So, it will give two ions in water.