Question
Question: The number of integral value of l for which x<sup>2</sup> + y<sup>2</sup> + 2l x + 2(1 –l)y –1 = 0 ...
The number of integral value of l for which
x2 + y2 + 2l x + 2(1 –l)y –1 = 0 is the equation of a circle whose radius can not exceed 3
A
3
B
4
C
5
D
None
Answer
4
Explanation
Solution
λ2+(1−λ)2+1< 3
l2 + l2 –2l + 1 + 1 < 9
2l2 –2l – 7 < 0
21+15
–1.45 < l < 2. 45
–1, 0, 1, 2