Question

The number of gram molecules of oxygen in $6.02 \times 10^{24}$ CO molecules is

• A. 10 g molecules
• B. 5 g molecules
• C. 1 g molecule
• D. 0.5 g molecule

Answer 1

Answer: (B)

5 g molecules

Answer 2

$6.023 \times 10^{23}$ molecules of CO = 1 mole of CO
$6.02 \times 10^{24}$ molecules of CO = 10 moles of CO
=$\, \, \, \, \, \, \, \, \, \, 10 \, g \, atoms \, of \, O$
=$\, \, \, \, \, \, \, \, \, \, 5 \, g \, molecules \, of \, O_2$