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Question: The number of geometrical isomers of the following compound CH<sub>3</sub>–CH=CH–CH=CH–C<sub>2</sub>...

The number of geometrical isomers of the following compound CH3–CH=CH–CH=CH–C2H5 is :

A

4

B

3

C

2

D

5

Answer

4

Explanation

Solution

Polyene containing more than one double bond and terminal are different so

no. of geometrical isomer = 2n ̃ 22 = 4