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Question: The number of electrons present in -1 C of charge is....

The number of electrons present in -1 C of charge is.

A

6×10186 \times 10^{18}

B

1.6×10191.6 \times 10^{19}

C

6×10196 \times 10^{19}

D

1.6×10181.6 \times 10^{18}

Answer

6×10186 \times 10^{18}

Explanation

Solution

By quantization of charge, q=ne or

n=qe=−1C−(1.6×10−19)=6×1018n = \frac{q}{e} = \frac{- 1C}{- (1.6 \times 10^{- 19})} = 6 \times 10^{18} electrons