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Question: The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 ...

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is: (charge on an electron is 1.60×1019C1.60\times {{10} ^{-19}}C):
(A) 3.75×10203.75\times {{10} ^ {20}}
(B) 7.48×10237.48\times {{10} ^ {23}}
(C) 6×10236\times {{10} ^ {23}}
(D) 6×10206\times {{10} ^ {20}}

Explanation

Solution

For calculating the number of electrons, we can use the formula: Q=Q= nene.
where QQ is the amount of electricity passed,
nn is the number of electrons liberated at the cathode,
ee is the charge on an electron,

Complete step by step solution:
We have been provided with charge on an electron: 1.60×1019C1.60\times {{10} ^ {-19}}C,
Also, during electrolysis current is: 1 ampere and time: 60seconds,
We need to find the number of electrons,
So, for that we will be using the formula: Q=Q= nene,
Where Q is the amount of electricity passed,
n is the number of electrons liberated at cathode,
e is the charge on an electron,
we have been given e in the question that is equal to: 1.60×1019C1.60\times {{10} ^ {-19}}C,
so, we will be calculating Q,
so, the formula for calculating the amount of electricity passed is: Q=i×tQ=i\times t,
so, we can keep this value of Q in: Q=ne,
Now, the equation becomes: i×t=n×ei\times t=n\times e,
So, the number of electrons liberated at cathode: n=i×ten=\dfrac {i\times t} {e},
Now, keeping the values in the above equation we would get: n=1×601.6×1019n=\dfrac {1\times 60} {1.6\times {{10} ^ {-19}}} ,
So, the number of electrons comes out to be: 3.75×10203.75\times {{10} ^ {20}} .

Therefore, we can conclude that option (A) is correct.

Note: A cathode is a metallic electrode through which current flows out in a polarized electrical device. Conversely, an anode is an electrode in a polarized electrical device through which current flows in from an outside circuit.