Question

The number of electrons delivered at the cathode during electrolysis by a current of $1$ ampere in $60$ seconds is (change on electron = $1.60 \times 10^{-19} C)$

• A. $6 \times 10^{23}$
• B. $6 \times 10^{20}$
• C. $3.75 \times 10^{20}$
• D. $7.48 \times 10^{23}$

Answer 1

Answer: (C)

$3.75 \times 10^{20}$

Answer 2

$Q = ne$
$I \times t = ne$
$n =\frac{1 \times 60}{1.6 \times 10^{-19}}$
$n =3.75 \times 10^{20}$