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Question: The number of d-electrons in \(F{{e}^{2+}}\) (Z = 26) is not equal to the number of electrons in whi...

The number of d-electrons in Fe2+F{{e}^{2+}} (Z = 26) is not equal to the number of electrons in which one of the following?
(a)- d-electrons in Fe (Z = 26)
(b)- p-electrons in Ne (Z = 10)
(c)- s-electrons in Mg (Z = 12)
(d)- p-electrons in Cl (Z = 17)

Explanation

Solution

First write the configuration of Fe in the ground state and then in Fe2+F{{e}^{2+}}, there is a removal of two electrons. Now compare all the configuration of the elements Fe, Ne, Mg, and Cl.

Complete answer:
Iron is the element that belongs to d-block so its configuration in ground state is given below:
1s22s22p63s23p64s23d61{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}4{{s}^{2}}3{{d}^{6}}
When there is an excitation of two electrons then the FeFe converts into Fe2+F{{e}^{2+}}. So from the above configuration, two electrons will be removed from the 4s4sorbital. So the configuration becomes:
1s22s22p63s23p63d61{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{6}}
Now, the electronic configuration of FeFe having atomic number 26 is:
1s22s22p63s23p64s23d61{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}4{{s}^{2}}3{{d}^{6}}
So, it has the same number of electrons in d-orbital as that of an electron in d-orbital of Fe2+F{{e}^{2+}}, i.e., 6 electrons.
In NeNe having atomic number 10, the electronic configuration is:
1s22s22p61{{s}^{2}}2{{s}^{2}}2{{p}^{6}}
So, it has the same number of electrons in p-orbital as that of an electron in p-orbital of Fe2+F{{e}^{2+}}, i.e., 6 electrons.
In MgMg having atomic number 12, the electronic configuration is:
1s22s22p63s21{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}
So, it has the same number of electrons in s-orbital as that of an electron in s-orbital of Fe2+F{{e}^{2+}}, i.e., (2+2+2) 6 electrons.
In ClCl having atomic number 17, the electronic configuration is:
1s22s22p63s23p51{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{5}}
So, the number of p-electrons in ClClis: 6+5=116+5=11. But in Fe2+F{{e}^{2+}}, the number of p-electrons is: 6+6=126+6=12. So they are not equal.

Therefore, the correct answer is an option (d)- p-electrons in Cl (Z = 17).

Note:
Magnesium is the element of s-block having atomic number 12 and its last electron comes in the s-orbital. Neon and chlorine are the elements of p-block having atomic numbers 10 and 17 respectively and their last electron comes in the p-orbital.